typescript 68 lines · 10 steps

A retry queue with exponential backoff

Persist failed requests in localStorage and replay them with growing delays until they succeed or exhaust their attempts.

Explained by highlit
1type QueuedRequest = {
2 id: string;
3 url: string;
4 method: string;
5 headers: Record<string, string>;
6 body: string | null;
7 attempts: number;
8 nextRetryAt: number;
9};
10 
11const STORAGE_KEY = "retry_queue";
12const MAX_ATTEMPTS = 5;
13const BASE_DELAY_MS = 1000;
14 
15function load(): QueuedRequest[] {
16 try {
17 return JSON.parse(localStorage.getItem(STORAGE_KEY) ?? "[]");
18 } catch {
19 return [];
20 }
21}
22 
23function save(queue: QueuedRequest[]): void {
24 localStorage.setItem(STORAGE_KEY, JSON.stringify(queue));
25}
26 
27export function enqueue(req: Omit<QueuedRequest, "id" | "attempts" | "nextRetryAt">): void {
28 const queue = load();
29 queue.push({
30 ...req,
31 id: crypto.randomUUID(),
32 attempts: 0,
33 nextRetryAt: Date.now(),
34 });
35 save(queue);
36}
37 
38export async function flush(): Promise<void> {
39 const now = Date.now();
40 const queue = load();
41 const remaining: QueuedRequest[] = [];
42 
43 for (const item of queue) {
44 if (item.nextRetryAt > now) {
45 remaining.push(item);
46 continue;
47 }
48 try {
49 const res = await fetch(item.url, {
50 method: item.method,
51 headers: item.headers,
52 body: item.body,
53 });
54 if (!res.ok) throw new Error(`HTTP ${res.status}`);
55 } catch {
56 const attempts = item.attempts + 1;
57 if (attempts < MAX_ATTEMPTS) {
58 remaining.push({
59 ...item,
60 attempts,
61 nextRetryAt: now + BASE_DELAY_MS * 2 ** attempts,
62 });
63 }
64 }
65 }
66 
67 save(remaining);
68}
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STEP 01

Walkthrough

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Three takeaways
  1. 1Persisting the queue to localStorage lets retries survive page reloads and browser restarts.
  2. 2Exponential backoff spaces out retries so a struggling server isn't hammered by immediate reattempts.
  3. 3Capping attempts prevents a permanently failing request from living in the queue forever.

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