python
31 lines · 5 steps
Building a human-friendly time_ago helper
Convert a datetime into a phrase like "3 days ago" by walking descending time intervals.
Explained by
highlit
1from datetime import datetime, timezone
2
3_INTERVALS = (
4 ("year", 60 * 60 * 24 * 365),
5 ("month", 60 * 60 * 24 * 30),
6 ("week", 60 * 60 * 24 * 7),
7 ("day", 60 * 60 * 24),
8 ("hour", 60 * 60),
9 ("minute", 60),
10 ("second", 1),
11)
12
13
14def time_ago(when: datetime, *, now: datetime | None = None) -> str:
15 if when.tzinfo is None:
16 when = when.replace(tzinfo=timezone.utc)
17 now = now or datetime.now(timezone.utc)
18
19 delta = int((now - when).total_seconds())
20 if delta < 0:
21 return "in the future"
22 if delta < 10:
23 return "just now"
24
25 for name, size in _INTERVALS:
26 count = delta // size
27 if count:
28 plural = "s" if count != 1 else ""
29 return f"{count} {name}{plural} ago"
30
31 return "just now"
01 / 01
STEP 01
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Three takeaways
- 1Ordering intervals from largest to smallest lets a single loop pick the coarsest unit that fits.
- 2Normalizing naive datetimes to UTC avoids errors when subtracting aware and naive values.
- 3Handling edge cases like future and near-zero deltas up front keeps the main logic clean.
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